7p^2+23p=6

Solution for 7p^2+23p=6 equation:

7p^2+23p=6

We move all terms to the left:

7p^2+23p-(6)=0

a = 7; b = 23; c = -6;
Δ = b2-4ac
Δ = 232-4·7·(-6)
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{697}}{2*7}=\frac{-23-\sqrt{697}}{14}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{697}}{2*7}=\frac{-23+\sqrt{697}}{14}
$